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Re: boole



Not bad!  However, I would push for (boole #b11111110 a b c) = (logior a b c).
Then we would have the pretty pattern that
	(logbit (boole op x1 x2 x3 ... xn) j)
	= (logbit op #b<z1><z2><z3>...<zn>) where <zk> = (logbit xk j)