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[no subject]

Awrighty, we've settled y^0=1.  If you want to worry about these things, 
you have + and - infinity, in the IEEE arithmetic. You need to specify
inf^(- inf)  = 0, 0^(-infinity) = infinity, (or should that be a division
by zero?)  And if you've gotten all that set up, we can start talking
about accuracy. :-)